89x^2+39x-50=0

Solution for 89x^2+39x-50=0 equation:

89x^2+39x-50=0

a = 89; b = 39; c = -50;
Δ = b2-4ac
Δ = 392-4·89·(-50)
Δ = 19321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19321}=139$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-139}{2*89}=\frac{-178}{178}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+139}{2*89}=\frac{100}{178}
=50/89
$